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12
0.5 mol×24=12.
Engineering admission · Other / specialist pathway · Chemistry
Integrate chemical quantities, structure and reaction reasoning.
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A demanding chemistry solution still begins with a correct formula and balanced equation. Equilibrium and rate are different questions. Organic reaction predictions require structure and conditions. Separate a theoretical maximum from observed recovery.
CaCO3 → CaO + CO2 has a 1:1 amount ratio. Using 100 g/mol for CaCO3, 25 g is 0.25 mol and can produce 0.25 mol CO2. At a stated ideal-gas molar volume of 24 dm³/mol, that is 6 dm³.
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12
0.5 mol×24=12.
3
−log10(10^-3)=3.
1
Its two carbon atoms share one double bond.
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It changes rates of both directions without changing the equilibrium constant.
Distinguish speed from equilibrium composition.
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12/16×100=75%; three quarters of the theoretical mass was recovered under the stated case.
Define the numerator and denominator and note possible recovery losses.
Write mole and structural solutions with stated conditions.
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