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6
2^6=64.
Class 11 · Bangla Version · Mathematics
Solve exponential and logarithmic equations with domains stated.
Original Kidemy Class 11 progression. This level has its own text, examples and questions. Curriculum versions share the progression; complete board-specific coverage still needs specification matching and additional material.
For positive a≠1, log_a x is the exponent producing x and requires x>0. Logarithm laws apply to products and powers, not arbitrary sums. Exponential growth assumes a specified rate over specified intervals.
log₂(32)=5. ln(x)+ln(2)=ln(10) gives 2x=10 and x=5, within x>0.
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6
2^6=64.
4
3^4=81.
1
e^0=1.
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The sum of logs equals ln(ab), not the log of a sum. For a=b=1, ln2 differs from 0.
Give a valid positive counterexample.
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x−1=100, so x=101, satisfying x>1.
State the logarithm argument restriction.
Create a logarithmic equation, solve it and reject any candidate outside its domain.
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